3.7.3 Integration, SPM Practice (Question 5 – 8)
Question 5: Given ∫ ( 6 x 2 +1 )dx=m x 3 +x +c, where m and c are constants, find (a) the value of m. (b) the value of c if ∫ ( 6 x 2 +1 )dx=13 when x=1. Solution: (a) ∫ ( 6 x 2 +1 )dx=m x 3 +x +c 6 x 3 3 +x+c=m x 3 +x+c 2 x 3 +x+c=m x 3 +x+c Compare the both sides, ∴ m=2 (b) … Read more