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SPM Additional Mathematics 2019, Paper 2 (Question 8)


Question 8:
Diagram 4 shows a dart’s target board at a dart game booth in a funfair.
Diagram 4

The booth offers 3 darts per game. The customers have to pay RM5 to play a game. A toy bear will be given to customers who are able to hit the bullseye for the three darts’ throws in a game. Bob is a dart player. By average, he hits the bullseye 7 times out of 10 darts thrown.

(a) Bob would play the game if he had at least 90% chance to win at least one toy bear by spending RM30.
By mathematical calculation, suggest to Bob whether he should play the game or otherwise. [4 marks]

(b) What is the minimum number of games that Bob needed so that he can get 4 toy bears? [4 marks]


Solution:
(a)
X~B( 3, 0.7 ) P( X=r )= C 3 r ( 0.7 ) r ( 0.3 ) 3r P( won a toy bear )=P( x=3 )                               = C 3 3 ( 0.7 ) 3 ( 0.3 ) 0                               =0.343 Y=Number of games in which Bob wins a toy bear. Y~B( n, 0.343 ) Number of games played by Bob= RM 30 RM 5                                                    =6

P( Y1 )0.90 1P( Y=0 )0.90 P( Y=0 )0.10 C n 0 ( 0.343 ) 0 ( 0.657 ) n 0.10 ( 0.657 ) n 0.10 n log 10 ( 0.657 ) log 10 0.10                      n5.481                      n=6
By playing 6 games, Bob had at least 90% chance to win at least one toy bear. Hence, Bob should play the game.

(b)
np ≥ 4
n(0.343) ≥ 4
n ≥ 11.66
n = 12
Minimum number of games = 12

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