\

5.2b Standard Normal Distribution Tables (Example 1)


5.2b Standard Normal Distribution Tables (Example 1)

Example 1:
Find the value of each of the following probabilities by reading the standard normal distribution tables.
(a) (Z > 0.600)
(b) (Z < –1.24)
(c) (Z > –1.1)
(d) (Z < 0.76)
 
Solution:
Standard Normal Distribution Table


*When reading the standard normal distribution tables, it involves subtraction of values.



(a)
From the standard normal distribution table,(Z > 0.600) = 0.2743


(b)
(Z < –1.24)
= (Z > 1.24)
= (1.24)
= 0.1075 ← (reading from the standard normal distribution table)


(*In the standard normal distribution table, all the values of are positive. As the curve is symmetrical about the vertical axis, the area of the shaded region in both of the graphs are the same.)



(c)
(Z > –1.1)
= 1 – Area P
= 1 – (–1.1)
= 1 – 0.1357 ← (reading from the standard normal distribution table)
= 0.8643

(d)
(Z < 0.76)
= 1 – Area P
= 1 – (0.76)
= 1 – 0.2236 ← (reading from the standard normal distribution table)
= 0.7764


Leave a Comment