5.2a z–Score of a Normal Distribution
Example:
(a) A normal distribution has a mean, µ = 50 and a standard deviation σ = 10. Calculate the standard score of the value X = 35.
(b) The masses of Form 5 students of a school are normally distributed with a mean of 60 kg and a standard deviation of 15 kg.
Find
(i) the standard score of the mass of 65 kg,
(ii) the mass of a student that corresponds to the standard score of – ½.
Solution:
(a)
X ~ N (µ, σ2).
X ~ N (50, 102)
(b)(i)
X – Mass of a Form 5 student
X ~ N (µ, σ2).
X ~ N (60, 152)
Hence, the standard score of the mass of 65 kg is ⅓.
(b)(ii)
Z = – ½,
Hence, the mass of a Form 5 student that corresponds to the standard score of – ½ is 52.5 kg.