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7.5.1 Probability, Paper 1 (Short Questions)


Question 1:
The probability of student P being chosen as a school prefect is 3 4  while the probability of student Q being chosen is 5 6 .
Find the probability that
(a) both of the students are chosen as the school prefect,
(b) only one student is chosen as a school prefect.

Solution:
(a)
Probability (both of the students are chosen as the school prefect ) = 3 4 × 5 6 = 5 8

(b)
Probability (only one student is chosen as a school prefect ) = ( 3 4 × 1 6 ) + ( 1 4 × 5 6 ) = 3 24 + 5 24 = 1 3


Question 2:
A bag contains x pink cards and 6 green cards. Two cards are drawn at random from the bag, one after the other, without replacement. Find the value of x if the probability of obtaining two green cards is .

Solution:
Total cards in the bag = x + 6
P(obtaining 2 green cards) =
6 x + 6 × 5 x + 5 = 1 3 30 ( x + 6 ) ( x + 5 ) = 1 3
(x + 6) (x + 5) = 90
x2 + 11x + 30 = 90
x2 + 11x – 60 = 0
(x – 4) (x + 15) = 0
x = 4   or   x = –15 (not accepted)



Question 3:
A sample space of an experiment is given by S = {1, 2, 3, … , 21}. Events Q and R are defined as follows:
Q : {3, 6, 9, 12, 15, 18, 21}
R : {1, 3, 5, 15, 21}

Find
(a) P(Q)
(b) P(Q and R)

Solution:
(a)

n( S )=21,n( Q )=7 P( Q )= 7 21 = 1 3

(b)
QR={ 3,15,21 }, then n( QR )=3 P( Q and R )=P( QR )    = n( QR ) n( S )   = 3 21   = 1 7


Question 4:
The events A and B are not independent.
Given P( A )= 3 5 ,P( B )= 1 4  and P( AB )= 1 5 , find (a) P[ ( AB )' ], (b) P( AB ).

Solution:
(a)
P[ ( AB )' ]=1P( AB )                      =1 1 5                      = 4 5

(b)
P( AB )=P( A )+P( B )P( AB )                 = 3 5 + 1 4 1 5                = 13 20

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