Processing math: 100%
\

2.9 Small Changes and Approximations

2.9 Small Changes and Approximations


If δx is very small, δyδx will be a good approximation of dydx, ,


This is very useful information in determining an approximation of the change in one variable given the small change in the second variable. 


Example:
Given that y = 3x2 + 2x – 4. Use differentiation to find the small change in y when x increases from 2 to 2.02.

Solution:
y=3x2+2x4dydx=6x+2

The small change in is denoted by δy while the small change in the second quantity that can be seen in the question is the x and is denoted by δx.

δyδxdydxδy=dydx×δxδy=(6x+2)×(2.022)δx=new xoriginal xδy=[6(2)+2]×0.02 Substitute x with the original value of x, i.e2.δy=0.28

Leave a Comment