1.5.7 Inverse Function Example 7

Example 7 (Comparison Method)
Given that $f:x\to \frac{2h}{x-3k}$ , x≠3k , where h and k are constants and $f^{-1}:x\to \frac{14+24x}{x}$ , x≠0, find the value of h and of k.

Solution: