Inverse Function Example 7 March 2, 2018November 16, 2013 by Example 7 (Comparison Method) Given that $f:x\to \frac{2h}{x-3k}$ , x≠3k , where h and k are constants and ${f}^{-1}:x\to \frac{14+24x}{x}$ , x≠0, find the value of h and of k. Solution: